Submit Time:2024-02-11 22:30:55

运行 ID: 40523

#include<iostream> using namespace std; int main(){ int n, m,cnt=0; int a[105][105],b[105][105]; cin>>n>>m; for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>a[i][j]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>b[i][j]; if(a[i][j]=b[i][j]) cnt++; } } double c=cnt*100.0/(n*m); printf("%,2f",c); return 0; }