| Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|
| 81100 | sh25_zhangjiajia | 被3整除的组合数(1) | C++ | Output Limit Exceeded | 0 MS | 180 KB | 231 | 2026-01-04 15:38:40 |
#include <cstdio> using namespace std; int main() { for(int i = 1; i <= 300; i++) for(int j = i + 1; j <= 300; j++) for(int k = j + 1; k <= 300; k++) if((i + j + k) % 3 == 0) printf("%d %d %d\n", i, j, k); return 0; }