| Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|
| 78270 | sh25_zhangjiajia | 对称平方数1 | C++ | Accepted | 1 MS | 248 KB | 499 | 2025-12-26 15:33:50 |
#include <iostream> using namespace std; bool isPalindrome(int n) { int original = n; int reversed = 0; // 反转数字 while (n > 0) { reversed = reversed * 10 + n % 10; n = n / 10; } // 比较反转后的数字与原数字 return original == reversed; } int main() { for (int i = 0; i <= 256; ++i) { int square = i * i; if (isPalindrome(square)) { cout << i << endl; } } return 0; }