Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|
51305 | 张思存 | [在线测评解答教程] 求和 | C++ | Accepted | 2 MS | 196 KB | 130 | 2024-09-20 19:33:12 |
#include<stdio.h> int main(){ int n; while (scanf("%d", &n) != EOF) { printf("%d\n", n * (n + 1) / 2 ); } return 0; }