Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
---|---|---|---|---|---|---|---|---|
38350 | LeeHao | 质因数分解 | C++ | Accepted | 1 MS | 252 KB | 199 | 2024-01-26 19:18:32 |
#include <bits/stdc++.h> using namespace std; int main() { int n, i; scanf("%d", &n); for (i = 2; n > 0; i++) { if (n % i == 0) { cout << n / i; return 0; } } return 0; }