| Run ID | Author | Problem | Lang | Verdict | Time | Memory | Code Length | Submit Time |
|---|---|---|---|---|---|---|---|---|
| 29251 | 惠子铭 | 求整数的和与均值 | C++ | Accepted | 0 MS | 196 KB | 203 | 2023-10-25 11:55:09 |
#include<stdio.h> int main() { int n,m,i; double sum; scanf("%d",&n); for (i=1;i<=n;i++) { scanf("%d",&m); if(m<=10000) sum+=m; } printf("%.0f %.5f\n",sum,sum/n); return 0; }